If three resistors 3 ohms, 5 ohms, and 22 ohms are connected in series in a 28 volt circuit, how much current will flow through the 3 ohm resistor?

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Multiple Choice

If three resistors 3 ohms, 5 ohms, and 22 ohms are connected in series in a 28 volt circuit, how much current will flow through the 3 ohm resistor?

Explanation:
In a series circuit the same current flows through every component, while the voltages add up across each resistor. First find the total resistance by adding them: 3 + 5 + 22 = 30 ohms. With 28 volts across the chain, the current is I = V / R = 28 / 30 ≈ 0.933 A, about 0.93 A. Since the current is the same through all resistors, the 3-ohm resistor also carries approximately 0.93 A. (For context, the voltage drop across that resistor would be I × R ≈ 0.933 × 3 ≈ 2.8 V.)

In a series circuit the same current flows through every component, while the voltages add up across each resistor. First find the total resistance by adding them: 3 + 5 + 22 = 30 ohms. With 28 volts across the chain, the current is I = V / R = 28 / 30 ≈ 0.933 A, about 0.93 A. Since the current is the same through all resistors, the 3-ohm resistor also carries approximately 0.93 A. (For context, the voltage drop across that resistor would be I × R ≈ 0.933 × 3 ≈ 2.8 V.)

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