As weighed, the total empty weight of an aircraft is 5862 lbs with a moment of 885957 in-lb. However, when weighed, 20 lbs of potable water were on board at +84 and 23 lbs of hydraulic fluid at +101. What is the empty weight CG?

As weighed, the total empty weight of an aircraft is 5862 lbs with a moment of 885957 in-lb. However, when weighed, 20 lbs of potable water were on board at +84 and 23 lbs of hydraulic fluid at +101. What is the empty weight CG?

• A. +151.365 inches
• B. +150.000 inches
• C. +152.000 inches
• D. +149.900 inches

Answer: (A)

The main idea is to find the center of gravity from total weight and total moment: CG = total moment / total weight. Start with the empty weight and its moment, then add the weights and their moments. Total weight = 5862 + 20 + 23 = 5905 lb. Total moment = 885,957 + (20×84) + (23×101) = 885,957 + 1,680 + 2,323 = 889,960 in-lb. Now compute the CG: 889,960 in-lb ÷ 5,905 lb ≈ 150.712 inches. The option closest to this value is the one around +151.37 inches, so that is the best pick.

The main idea is to find the center of gravity from total weight and total moment: CG = total moment / total weight.

Start with the empty weight and its moment, then add the weights and their moments. Total weight = 5862 + 20 + 23 = 5905 lb. Total moment = 885,957 + (20×84) + (23×101) = 885,957 + 1,680 + 2,323 = 889,960 in-lb.

Now compute the CG: 889,960 in-lb ÷ 5,905 lb ≈ 150.712 inches.

The option closest to this value is the one around +151.37 inches, so that is the best pick.